Online Access Free C9050-042 Practice Test
| Exam Code: | C9050-042 |
| Exam Name: | Developing with IBM Enterprise PL/I |
| Certification Provider: | IBM |
| Free Question Number: | 140 |
| Posted: | Jul 21, 2026 |
Requirement Copy a dataset of record length 100 to another dataset.
If the following code does not fulfill the requirement above, which is the most likely reason?
DCL DDIN FILE RECORD INPUT;
DCL DDOUT FILE RECORD OUTPUT;
DCL INSTRUC CHAR(100);
DCL EOF_IN BIT(1) INIT('0'B);
ON ENDFILE(DDIN) EOF_IN = '1'B;
READ FILE(DDIN) INTO(INSTRUC);
DO WHlLE(^EOF_IN);
WRITE FILE(DDOUT) FROM(INSTRUC);
READ FILE(DDIN) INTO(INSTRUC);
WRITE FILE(DDOUT) FROM(INSTRUC);
END;
In which of the following groups of compiler options could all the options specified cause the compiler to
generate code which requires more time at execution?
Given the following code, which call will pass a dummy argument?
PROG: PROC OPTIONS(MAIN);
DCL SUM01 DEC FIXED(5,0) INIT (7);
DCL SUM02 DEC FIXED(9,0) INIT (999);
CALL SUBA(SUM01,
SUM02);
CALL SUSB(SUM01,
SUM02);
CALL SUBC(SUM01,
SUM02);
CALL SUBD(SUM01,
SUM02);
SUBA PROC( PRM1,
PRM2);
DCL PRM1 DEC FIXED (5,0) BYVALUE,
PRM2 DEC FIXED (9,0);
END SUBA;
SUBB:PROC( PRM1,
PRM2);
DCL PRM1 DEC FIXED (5,0),
PRM2 DEC FIXED (9,0);
END SUBD;
SUBC: PROC( PRM 1,
PRM2);
DCL PRM1 BIN FIXED (15,0),
PRM2 DEC FIXED (9,0);
END SUBC;
SUBD:PROC( PRM 1,
PRM2);
DCL PRM1 DEC FIXED(5,0) BYADDR,
PRM2 DEC FIXED (9,0) SYADDP;
END SUBD;
END PROG;