Free Access Oracle.1z0-071.v2023-10-02.q276 Practice Test (Page 45)

Question 216

Which two statements are true about the results of using the INTERSECToperator in compound queries?
(Choose two.)

A.Column names in each SELECTin the compound query can be different.

B.INTERSECTignores NULLs.

C.Reversing the order of the intersected tables can sometimes affect the output.

D.The number of columns in each SELECTin the compound query can be different.

E.INTERSECTreturns rows common to both sides of the compound query.

Question 217

View the exhibit and examine the description of the PRODUCT_INFORMATION table.
Which SQL statement would retrieve from the table the number of products having LIST_PRICE as NULL?

A.SELECT COUNT (DISTINCT list_price)FROM product_informationWHERE list_price is NULL

B.SELECT COUNT (NVL(list_price, 0))FROM product_informationWHERE list_price is NULL

C.SELECT COUNT (list_price)FROM product_informationWHERE list_price i= NULL

D.SELECT COUNT (list_price)FROM product_informationWHERE list_price is NULL

Question 218

View the exhibit and examine the structure in ORDERSand ORDER_ITEMStables.

You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATEVIEWstatement would create the views successfully?

A.CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date;

B.CREATE OR REPLACE VIEW ord_vu (order_id, order_date)
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
" NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date;

C.CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id) ||
"NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
WHITH CHECK OPTION;

D.CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
" NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date;

Question 219

The BOOKS_TRANSACTIONStable exists in your database.
Examine the SQL statement:
SQL>SELECT * FROM books_transactionsORDER BY 3;
What is the outcome on execution?

A.Rows are displayed in the order that they are stored in the table only for the three rows with the lowest values in the key column.

B.The execution tails unless the numeral 3 in the order by clause is replaced by a column name,

C.Rows are displayed in the order that they are stored in the table only for the first three rows.

D.Rows are displayed sorted in ascending order of the values in the third column in the table.

Question 220

View the exhibit and examine the structure in ORDERS and ORDER_ITEMS tables.

You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATE VIEW statement would create the view successfully?

A.CREATE OR REPLACE VIEW ord_vu (order_id, order_date)AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id, o.order_date;

B.CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date;

C.CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)||'NO OF ITEMS'FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_dateWHITH CHECK OPTION;

D.CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date;

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Question 216

Question 217

Question 218

Question 219

Question 220

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