Free Access Oracle.1z1-071.v2022-04-30.q200 Practice Test (Page 7)

Question 26

View the Exhibit and examine the structure of the ORDERS table.

You must select ORDER_ID and ORDER_DATE for all orders that were placed after the last order placed by CUSTOMER_ID 101.
Which query would give you the desired result?

A.SELECT order_id, order_date FROM orders
WHERE order_date >
ANY
(SELECT order_date FROM orders WHERE customer_id = 101);

B.SELECT order_id, order_date FROM orders
WHERE order_date > ALL
(SELECT order_date FROM orders WHERE customer_id = 101);

C.SELECT order_id, order_date FROM orders
WHERE order_date > ALL
(SELECT MAX(order_date) FROM orders ) AND customer_id = 101;

D.SELECT order_id, order_date FROM orders
WHERE order_date > IN
(SELECT order_date FROM orders WHERE customer_id = 101);

Question 27

View the Exhibit and examine the structure of ORDERS and CUSTOMERS tables.

There is only one customer with the cust_last_name column having value Roberts. Which INSERT statement should be used to add a row into the ORDERS table for the customer whose CUST_LAST_NAME is Roberts and CREDIT_LIMIT is 600?

A.INSERT INTO ordersVALUES(1, '10-mar-2007', 'direct',(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' ANDcredit_limit=600), 1000);

B.INSERT INTO orders (order_id, order_data, order_mode,(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' ANDcredit_limit=600), order_total)VALUES (1,
'10-mar-2007', 'direct', &customer_id, 1000).

C.INSERT INTO orders (order_id, order_data, order_mode,(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' ANDcredit_limit=600), order_total)VALUES(1,
'10-mar-2007', 'direct', &&customer_id, 1000);

D.INSERT INTO(SELECT o.order_id, o.order_date, o.order_mode, c.customer_id, o.order_totalFROM orders o, customers cWHERE o.customer_id = c.customer_idAND c.cust_last_name='Roberts' AND c.credit_limit=600 )VALUES (1, '10-mar-2007', 'direct', (SELECT customer_idFROM customersWHERE cust_last_name='Roberts' ANDcredit_limit=600), 1000);

Question 28

You want to display the date for the first Monday of the next month and issue the following command:

What is the outcome?

A.It executes successfully and returns the correct result.

B.In generates an error because TO_CHAR should be replaced with TO_DATE.

C.In generates an error because fm and double quotation marks should not be used in the format string.

D.In generates an error because rrrr should be replaced by rr in the format string.

E.It executes successfully but does not return the correct result.

Question 29

Which two statements are true about conditional INSERT ALL? (Choose two.)

A.The total number of rows inserted is always equal to the number of rows returned by the subquery.

B.Each row returned by the subquery can be inserted into only a single target table.

C.It cannot have an ELSEclause.

D.A single WHEN condition can be used for multiple INTOclauses.

E.Each WHENcondition is tested for each row returned by the subquery.

Question 30

View the exhibit and examine the structure in ORDERSand ORDER_ITEMStables.

You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATEVIEWstatement would create the views successfully?

A.CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date;

B.CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
" NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date;

C.CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id) ||
" NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date
WHITH CHECK OPTION;

D.CREATE OR REPLACE VIEW ord_vu (order_id, order_date)
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
" NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date;

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Question 26

Question 27

Question 28

Question 29

Question 30

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