Free Access Oracle.1z1-071.v2022-04-30.q200 Practice Test (Page 8)

Question 31

View the Exhibit and examine the structure of the PROMOTION table.

You have to generate a report that displays the promo named start data for all promos that started after that last promo in the 'INTTERNET' category.

A.SELECT promo_neme, promo_being_date FROM promotions
WHERE promo_being_date > All (SELECT promo_beinjg-date
FROM promotions
WHERE promo_category ='INTERNET' );

B.Select promo_name, promo_being_date FROM promoptions
WHERE promo_being_data > ANY (SELCT promo_being-date
FROM promotions
WHERE promo_category = 'INTERNET'

C.SELECT promo-name, promo-being_date FROM promotion
WHERE promo-being-date IN (SELECT promo_biing_date
FROM promotions
WHERE promo_category='INTYERNET');

D.SELECT promo-name, promo-being _date FROM promotions
Where promo_being_data >ALL (SELECT MAX (promo_being-date)
FROM promotions ) AND
Promo-category ='INTERNET';

Question 32

Examine the commands used to create DEPARTMENT_DETAILSand COURSE_DETAILS tables:

You want to generate a list of all department IDs that do not exist in the COURSE_DETAILStable.
You execute the SQL statement:

What is the outcome?

A.It fails because the ON clause condition is not valid.

B.It executes successfully but displays an incorrect list.

C.It fails because the join type used is incorrect.

D.It executes successfully and displays the required list.

Question 33

Examine this query:
SELECT TRUNC(ROUND(156.00, -2), -1) FROM DUAL;
What is the result?

A.16

B.200

C.100

D.160

E.150

Question 34

Which three statements are true regarding the usage of the WITH clause in complex correlated subqueries: (Choose three.)

A.If the query block name and the table name are the same, then the table name takes precedence.

B.The WITH clause can hold more than one query.

C.The query name in the WITH clause is visible to other query blocks in the WITH clause as well as to the main query block

D.It can be used only with the SELECT clause.

Question 35

Examine the data in the EMPLOYEES table:

Which statement will compute the total annual compensation for each employee?

A.SELECT last_ name (monthly_ salary+ monthly_ commission _ pct) *12 AS annual_
FROM employees ;

B.SELECT last name, (monthly_ salary *12) + (monthly_ salary * 12 * NVL
(monthly commission pct,0) ) As annual _ comp
FROM employees;

C.SELECT last name,
(monthly salary*12) + (monthly_commission_pct * 12) AS
annual comp
FROM employees
;

D.SELECT last_ name, monthly_ salary*12) + (monthly_ salary * 12 * Monthly commission _Pct) AS
annual_ comp
FROM employees;

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Question 31

Question 32

Question 33

Question 34

Question 35

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