What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main(int argc, char *argv[]) {
char *s = "ABCDEF";
cout << s+2;
return 0;
}

What happens when you attempt to compile and run the following code?

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
void fun(int i);
int main()
{
int i=0;
i++;
for (i=0; i<=5; i++)
{
fun(i);
}
return 0;
}
void fun(int i)
{
if (i==3)
return;
cout << i;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class First
{
public:
virtual void Print(){ cout<<"from First";}
};
class Second:public First
{
public:
void Print(){ cout<< "from Second";}
};
void fun(First *obj);
int main()
{
First FirstObject;
fun(&FirstObject);
Second SecondObject;
fun(&SecondObject);
}
void fun(First *obj)
{
obj?>Print();
}

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
int x;
protected:
int y;
public:
int z;
};
class B : public A {
string name;
public:
void set() {
y = 2;
z = 3;
}
void Print() { cout << y << z; }
};
int main () {
B b;
b.set();
b.Print();
return 0;
}