What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
const int size = 3;
class A {
public:
string name;
A() { name = "Bob";}
A(string s) { name = s;}
A(A &a) { name = a.name;}
};
class B : public A {
public:
B() { }
B(string s) : A(s) { }
void Print() {
cout << name;
}
};
int main () {
B b1("Alan");
b1.Print();
return 0;
}

How many times will the program print "HELLO" ?
#include <iostream>
using namespace std;
int main()
{
cout<<"HELLO";
main();
return 0;
}

What happens when you attempt to compile and run the following code?

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class Second;
class Base {
int age;
public:
Base () { age=5; };
friend void set(Base &ob, Second &so);
void Print() { cout << age;}
};
class Second {
string name;
public:
friend void set(Base &ob, Second &so);
void Print() { cout << name;}
};
void set(Base &ob, Second &so) {
ob.age = 0; so.name = "Bill";
}
int main () {
Base a;
Second b;
set(a,b);
a.Print();
b.Print();
return 0;
}

Given:
#include <iostream>
#include <exception>
using namespace std;
int main () {
try
{
int * myarray= new int[1000];
}
catch (bad_alloc&)
{
cout << "Error allocating memory";
}
catch (exception& e)
{
cout << "Standard exception";
}
catch (...)
{
cout << "Unknown exception";
}
return 0;
}
What will happen if we use the operator "new" and the memory cannot be allocated?