What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int compare(int, int);
int main()
{
int x = compare(10, 20);
cout << x;
return 0;
}
int compare(int i, int j)
{
return i<j;
}

Which code, inserted at line 15, generates the output "5 Bob"?
#include <iostream>
#include <string>
using namespace std;
class B;
class A {
int age;
public:
A () { age=5; };
friend void Print(A &ob, B &so);
};
class B {
string name;
public:
B () { name="Bob"; };
//insert code here
};
void Print(A &ob, B &so) {
cout<<ob.age << " " << so.name;
}
int main () {
A a;
B b;
Print(a,b);
return 0;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
int x;
protected:
int y;
public:
int z;
};
class B : public A {
string name;
public:
void set() {
y = 2;
z = 3;
}
void Print() { cout << y << z; }
};
int main () {
B b;
b.set();
b.Print();
return 0;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
namespace myNamespace1
{
int x = 5;
int y = 10;
}
namespace myNamespace2
{
float x = 3.14;
float y = 1.5;
}
int main () {
{
using namespace myNamespace1;
cout << x << " ";
}{
using namespace myNamespace2;
cout << y;
}
return 0;
}

Which code, inserted at line 12, generates the output "5b"?
#include <iostream> using namespace std; namespace myNamespace1 { int var = 5; } namespace myNamespace2 { char var = 'b'; } int main () { //insert code here return 0; }