What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class A
{
public:
void Print(){ cout<<"A";}
};
class B:public A
{
public:
void Print(){ cout<< "B";}
};
int main()
{
A *obj;
A ob1;
obj = &ob1;
obj?>Print();
B ob2;
obj = &ob2;
obj?>Print();
}

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
int main()
{
string s1[]= {"H" , "t" };
string s;
for (int i=0; i<2; i++) {
s = s1[i];
s.insert(1,"o");
cout << s;
}
return( 0 );
}

What is the output of the program if characters 'h', 'e', 'l', 'l' , 'o' and enter are supplied as input?
#include <iostream>
#include <string>
using namespace std;
void f();
int main()
{
f();
return 0;
}
void f()
{
char c;
c = cin.get();
cout << c;
if(c != '\n')
f();
}

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class A {
public :
void print() {
cout << "A ";
}
};
class B {
public :
void print() {
cout << "B ";
}
};
int main() {
B sc[2];
A *bc = (A*)sc;
for (int i=0; i<2;i++)
(bc++)->print();
return 0;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int x=5;
static int y;
int i=0;
void static myFunction()
{
y=x++ + ++i;
}
int main (int argc, const char * argv[])
{
x++;
myFunction();
cout<<y<<" "<<x<< " " << i;
}