What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class A {
public:
void Print(){ cout<<"A";}
};
class B:public A {
public:
virtual void Print(){ cout<< "B";}
};
class C:public B {
public:
void Print(){ cout<< "C";}
};
int main()
{
A ob1;
B ob2;
C ob3;
B *obj;
obj = &ob2;
obj?>Print();
obj = &ob3;
obj?>Print();
}

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class complex{
double re, im;
public:
complex() : re(1),im(0.4) {}
complex operator+(complex &t);
void Print() { cout << re << " " << im; }
};
complex complex::operator+ (complex &t){
complex temp;
temp.re = this?>re + t.re;
temp.im = this?>im + t.im;
return temp;
}
int main(){
complex c1,c2,c3;
c3 = c1 + c2;
c3.Print();
}

Given:
#include <iostream>
#include <exception>
using namespace std;
int main () {
try
{
int * myarray= new int[1000];
}
catch (bad_alloc&)
{ cout << "Error allocating memory"; } catch (exception& e) { cout << "Standard exception"; } catch (...) { cout << "Unknown exception"; } return 0; }
What will happen if we use the operator "new" and the memory cannot be allocated?

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main(int argc, char *argv[]) {
char *s = "ABCDEF";
cout << s+2;
return 0;
}

How could you pass arguments to functions?