What is the output of the program?
#include <iostream>
using namespace std;
#define PRINT(i) cout<<i;
int main()
{
int y=2, z=3;
PRINT(y);
PRINT(z);
return 0;
}

Given:
#include <iostream>
#include <exception>
using namespace std;
int main () {
try
{
int * myarray= new int[1000];
}
catch (bad_alloc&)
{ cout << "Error allocating memory"; } catch (exception& e) { cout << "Standard exception"; } catch (...) { cout << "Unknown exception"; } return 0; }
What will happen if we use the operator "new" and the memory cannot be allocated?

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main(){
int i = 1;
if (i++==1) {
cout << i;
} else {
cout << i-1;
}
return 0;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
void fun(int*);
int main()
{
int *x;
int i=2;
x=&i;
fun(x);
cout<<i;
return 0;
}
void fun(int *i)
{
*i = *i * *i;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class A {
public:
void Print(){ cout<<"A";}
};
class B:public A {
public:
virtual void Print(){ cout<< "B";}
};
class C:public B {
public:
void Print(){ cout<< "C";}
};
int main()
{
A ob1;
B ob2;
C ob3;
B *obj;
obj = &ob2;
obj?>Print();
obj = &ob3;
obj?>Print();
}