What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
const int size = 3;
class A {
public:
string name;
A() { name = "Bob";}
A(string s) { name = s;}
A(A &a) { name = a.name;}
};
class B : public A {
public:
int *tab;
B() { tab = new int[size]; for (int i=0; i<size; i++) tab[i]=1;}
B(string s) : A(s) { tab = new int[size]; for (int i=0; i<size; i++) tab[i]=1;}
~B() { delete tab; }
void Print() {
for (int i=0; i<size; i++) cout << tab[i];
cout << name;
}
};
int main () {
B b1("Alan");
B b2;
b1.tab[0]=0;
b1.Print(); b2.Print();
return 0;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
public:
int x;
A() { x=0;}
};
class B {
public:
int x;
B() { x=1;}
};
class C :public A, public B {
public:
int x;
C(int x) {
this->x = x;

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int x=5;
static int y=0;
void myFunction(int a)
{
y=++a;
}
int main (int argc, const char * argv[])
{
int i=0;
myFunction(i);
cout<<y<<" "<<x;
}

Which code, inserted at line 12, generates the output "5b"?
#include <iostream> using namespace std; namespace myNamespace1 { int var = 5; } namespace myNamespace2 { char var = 'b'; } int main () { //insert code here return 0; }

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
#define DEF_A 0
int main(int argc, char *argv[]) {
cout << DEF_A;
return 0;
}