What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class A {
public :
void print() {
cout << "A ";
}
};
class B {
public :
void print() {
cout << "B ";
}
};
int main() {
B sc[2];
A *bc = (A*)sc;
for (int i=0; i<2;i++)
(bc++)->print();
return 0;
}

How could you pass arguments to functions?

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class complex{
double re, im;
public:
complex() : re(1),im(0.4) {}
complex operator?(complex &t);
void Print() { cout << re << " " << im; }
};
complex complex::operator? (complex &t){
complex temp;
temp.re = this->re ? t.re;
temp.im = this->im ? t.im;
return temp;
}
int main(){
complex c1,c2,c3;
c3 = c1 ? c2;
c3.Print();
}

What is the output of the program if character 4 is supplied as input?
#include <iostream>
using namespace std;
int main () {
int c;
cin >> c;
try
{
switch (c)
{
case 1:
throw 20;
case 2:
throw 5.2f;
case 3:
throw 'a';
default:
cout<<"No exception";
}
}
catch (int e)
{ cout << "int exception. Exception Nr. " << e; }
catch (float e)
{ cout << "float exception. Exception Nr. " << e; }
catch (...)
{ cout << "An exception occurred."; }
return 0;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class A
{
public:
void Print(){ cout<<"A";}
};
class B:public A
{
public:
void Print(){ cout<< "B";}
};
int main()
{
A *obj;
A ob1;
obj = &ob1;
obj?>Print();
B ob2;
obj = &ob2;
obj?>Print();
}