What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
int x=0;
int *ptr;
ptr = &x;
cout<<x<<" "<<*ptr;
return 0;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
int x,y=10;
float f;
f = 5.20;
x=(int) f;
cout << x <<", ";
f=float (y);
cout << f;
return 0;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
protected:
int y;
public:
int x,z;
A() : x(1), y(2), z(0) { z = x + y; }
A(int a, int b) : x(a), y(b) { z = x + y;}
void Print() { cout << z; }
};
class B : public A {
public:
int y;
B() : A() {}
B(int a, int b) : A(a,b) {}
void Print() { cout << z; }
};
int main () {
A b;
b.Print();
return 0;
}

Which code, inserted at line 8, generates the output "100"?
#include <iostream>
using namespace std;
int fun(int);
int main()
{
int *x = new int;
*x=10;
//insert code here
return 0;
}
int fun(int i)
{
return i*i;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int fun(int x) {
return 2*x;
}
int main(){
int i;
i = fun(1) || fun(2);
cout << i;
return 0;
}