What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
int x;
protected:
int y;
public:
int z;
};
class B : private A {
string name;
public:
void set() {
x = 1;
}
void Print() {
cout << x;
}
};
int main () {
B b;
b.set();
b.Print();
return 0;
}

Which of the following structures are correct?
1:
struct s1{ int x; char c;
};
2:
struct s2{ float f; struct s2 *s;
};
3:
struct s3{ float f; in i;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
int *t;
t = new int[2];
for (int i=0; i<2; i++) {
t[i] = i;
}
cout << t[1];
}

What will the variable "y" be in class B?
class A {
int x;
protected:
int y;
public:
int age;
};
class B : private A {
string name;
public:
void Print() {
cout << name << age;
}
};

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class B;
class A {
int age;
public:
A () { age=5; };
friend class B;
};
class B {
string name;
public:
B () { name="Bob"; };
void Print(A ob) {
cout << name << ob.age;
}
};
int main () {
A a;
B b;
b.Print(a);
return 0;
}