What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
#define DEF_A 0
#define DEF_B DEF_A+1
#define DEF_C DEF_B+1
int main(int argc, char *argv[]) {
cout << DEF_C;
return 0;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
int x;
protected:
int y;
public:
int z;
A() { x=1; y=2; z=3; }
};
class B : public A {
public:
void set() {
y = 4; z = 2;
}
void Print() {
cout << y << z;
}
};
int main () {
B b;
b.set();
b.Print();
return 0;
}

Which code, inserted at line 18, generates the output "AB"
#include <iostream>
using namespace std;
class A
{
public:
void Print(){ cout<< "A";}
void Print2(){ cout<< "a";}
};
class B:public A
{
public:
void Print(){ cout<< "B";}
void Print2(){ cout<< "b";}
};
int main()
{
B ob2;
//insert code here
ob2.Print();
}

What happens when you attempt to compile and run the following code?

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class SampleClass
{
string *s;
public:
SampleClass() { s = new string("Text");}
SampleClass(string s) { this?>s = new string(s);}
~SampleClass() { delete s;}
void Print(){ cout<<*s;}
};
int main()
{
SampleClass *obj;
obj = new SampleClass("Test");
obj?>Print();
}