What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
protected:
int y;
public:
int x;
int z;
A() { x=2; y=2; z=3; }
A(int a, int b) : x(a), y(b) { z = x ? y;}
void Print() {
cout << z;
}
};
int main () {
A a(2,5);
a.Print();
return 0;
}

Which code, inserted at line 5, generates the output "ABC"?
#include <iostream>
using namespace std;
class A {
public:
//insert code here
};
class B:public A {
public:
void Print(){ cout<< "B"; }
};
class C:public B {
public:
void Print(){ cout<< "C"; }
};
int main()
{
A ob1;
B ob2;
C ob3;
A *obj;
obj = &ob1;
obj?>Print();
obj = &ob2;
obj?>Print();
obj = &ob3;
obj?>Print();
}

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
public:
int x;
};
class B : public A {
public:
B() { x=1;}
B(int x) {this?>x = x;}
};
int main () {
B c1;
B c2(10);
cout << c1.x;
cout << c2.x;
return 0;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
int x;
protected:
int y;
public:
int z;
A() { x=1; y=2; z=3; }
};
class B : public A {
string z;
public:
void set() { y = 4; z = "John"; }
void Print() { cout << y << A::z; }
};
int main () {
B b;
b.set();
b.Print();
return 0;
}

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
void fun(int*);
int main()
{
int *x;
int i=2;
x=&i;
fun(x);
cout<<i;
return 0;
}
void fun(int *i)
{
*i = *i * *i;
}